calculus

Temi philip

who knws how to integrate

0 04-03-2016 15:29:00 +0000

Holarmidey adaramola

write out your question

0 04-03-2016 15:36:00 +0000

Temi philip

integrate cos^2 with respect to tita pls snap out ur solution and post

0 04-03-2016 15:52:00 +0000

Chidd Azoro

Just go and revise ur pasr qustn frm 2013 - 2015

0 04-03-2016 16:01:00 +0000

Temi philip

i dae wait oo

0 04-03-2016 16:02:00 +0000

Emmanuel Iwara(Tutor)

@Temi Philip. Let cos^2tita = 1/2[1 + cos2tita]ditita integrating each term will give 1/2[integral of tita detita + integral of cos2tita dedita] .Integrating integral of tita detita will give tita + the integration of integral of cos2tita dedita will give us 1/2sin2tita.therefore the integration of cos^2tita = 1/2[ tita +1/2sin2tita] = tita/2 + 1/4sin2tita + c

0 04-03-2016 16:30:00 +0000

Temi philip

pls could u post the solution

0 04-03-2016 17:40:00 +0000

Emmagreen Emmanuel

Who wrote 1:30pm

0 04-03-2016 18:27:00 +0000

Emmanuel Iwara(Tutor)

∫cos²ΘdΘ = ∫1/2[1 + cos2Θ]dΘ

∫cos²ΘdΘ = 1/2[∫dΘ + ∫cos2ΘdΘ]

∫cos²ΘdΘ = 1/2[Θ + 1/2cos2Θ]

∫cos²ΘdΘ = 1/2Θ + 1/2 x1/2cos2Θ+ c = 1/2Θ + 1/4cos2Θ+ c

0 07-03-2016 15:37:00 +0000

Susan David

how about calculus

0 08-03-2016 11:59:00 +0000

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