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03-03-2016 12:03:00 +0000
Good day all!
This session has ended for today
Algebraic Fraction is most foundamental to all who want to know mathematics and often tested by jamb and other exams.
Under algebraic expressions,fractions have same fundemental approach as done in arithmetical processes.
An algeraic fraction is the one in which the denominator is an algebraic expression.
e.g 4/x is an algeraic fraction but x/4 is not an algebraic fraction.
Simplification of fractions means that the fractions are to be written in their reduced forms, the process involves finding the L.c.m of the denominators,expressing each fraction as a fraction with the common denominator.
1.Dealing with addition or subtraction of fractions requires a common denominator.
2. multiply EVERY TERM in the equation by the common denominator. In an equation, (unlike an expression), you may multiply "every term" on both sides of the equal sign by the same value and not change the equation.
Example 1.Simplify 2x2 - 3ax + 4x2 -6xa -x2
Collection of like terms yield
2x2 + 4x2-x2 -3ax -6ax
= 6x2 -x2 -3ax -6ax
= 5x2 -9ax.
Example 2. Simplify (2 / x-2) -(3 / x-1)
taking L.C.M = (x -2)(x-1) and simplifying
Hence (2 / x-2) -( 3/ x-1) = [2(x-1) -3(x-2)] / [(x -2)(x-1)]
= [2x -2 -3x + 6] / [(x -2)(x-1)]
= (4 -x) / (x-2)(x-1).
Example 3.Simplify [3a3 / 3a2 -6ab] + [4b3/ 2b2 - ab]
Factorizing the denominators we have
[3a3 / 3a(a-2b)] + [4b3/ b(2b-a)], cancelling out common terms
= (a2) / (a-2b) + (4b2)/(2b-a)
= (a2)/ (a-2b) -(4b2)/(a-2b)
Taking L.C.M = (a-2b) and simplifying
= (a2 -4b2) / (a -2b)
applying differences of two sqaure in the numerator will yield
(a+2b)(a-2b) / (a-2b)
= a + 2b.
Example 4.Simplify (6-x-x2) / (x2 -4)
= (3 + x)(2-x) / (x+2)(x-2)
= -(3 + x)(2-x) / (x + 2)(2-x)]
= -(3 + x) / (x + 2)
Example 5.Evalute [ab2 -c2]/ 2bc + [a2]/ 2b + c]
When (a = 2, b = -3 and c = -2)
Substituting the values of a, b,and c into [ab2 -c2]/ 2bc + [a2]/ 2b + c]
[2(-3)2 -(-2)2] + / 2(-3) + (-2)]
= (2 x 9 -4)/ 12 + 4/(-6 -2)
= (14/12 - 4/8)
You may ask your questions if you have any, and i will try the best i can to give solutions to them.
Now try and see if you can solve the following past jamb and other exams questions.
1.Simplify 2a2 - a + 6a2-8a2-6a + 5a2 + 10a.
2.Simplify (x2 - y2)/(x2 + xy)
3. Simplify [15 - 2x - x2]/ [x2 -9]
4.Simplify x/(x + y) + y/(x -y) -(x2)/(x2 -y2)
5.If a = 2, b = -2 and c = -1/2, evalute (ab2-bc2)(a2c -abc)
Don't forget to fill our the survey after the session:
Survey Feedback Link - http://goo.gl/forms/Tasr40Ck1Z
I'm glad to be back in class.
03-03-2016 12:26:00 +0000
03-03-2016 12:30:00 +0000
No.5 = - 85/4
03-03-2016 12:57:00 +0000
03-03-2016 13:10:00 +0000
No. 3 = [x - 5] / [x - 3]
03-03-2016 13:11:00 +0000
hw did u gt dat no 3 @ omotayo
03-03-2016 13:12:00 +0000
No.3 = [x + 3] [x - 5] / [x + 3] [x - 3] = [x - 5] / [x - 3]
03-03-2016 13:15:00 +0000
03-03-2016 13:17:00 +0000
@Omotayo thanks for having No.3, No.1, right but you have to check the working solution of No.5
03-03-2016 14:07:00 +0000
Hello class feel free to ask your questions, am here to give solutions to your questions.
03-03-2016 14:12:00 +0000