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• # frequency

Mathematics

umeokeke kingsley
03-03-2016 11:29:00 +0000

please help me on this.........if 5,8,6 and 2 occur with frequencies 3,2,4 and 1 respectively,find the product of the modal and the median number

modal=6 mean=5.7

0 03-03-2016 11:37:00 +0000

• Ganiu Alimi

modal=6, mean=5.25

0 03-03-2016 11:49:00 +0000

• Ganiu Alimi

median=5.5, product of median and modal=33

0 03-03-2016 11:51:00 +0000

• Omotayo Olalekan

The product of Median and Modal = 35.

0 03-03-2016 12:09:00 +0000

• Omotayo Olalekan

The modal is 5 while the median = 8+6/2 = 7. So the product of both = 7 * 5 = 35.

0 03-03-2016 12:10:00 +0000

• Omotayo Olalekan

Sorry the modal is 6 while the median is = 8 + 6 / 2 = 7. So the product = 6 * 7 = 42.

0 03-03-2016 12:12:00 +0000

• Emmanuel Iwara(Tutor)

@Umeokeke Kingsley. The Modal class = 6, Median = (8+6)/2 = 14/2 =7 Hence their product = 6 x 7 = 42.

0 03-03-2016 12:13:00 +0000

• umeokeke kingsley

thanks

0 03-03-2016 12:42:00 +0000

• Ganiu Alimi

I want to ask, arnt we suppose to rearrange the from the lowest to the highest?

0 03-03-2016 14:13:00 +0000

• Rabiu Olawale

in ascending order..2,5,6,8 5+6=11. so 11รท2=5.5. i.e median number is =5.5. modal number is=6. therefore product for modal= 6*6=36

0 04-03-2016 16:51:00 +0000