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Mathematics

29-01-2016 15:39:00 +0000

This is another questions from jamb 2006, in which over 90% of the participant fail,now give a try and see if you can have it correct.
Question 4: Find the value of x for which the function 3x3= 9x2 is minimum
A. 3 B. 2 C. 0 D. 5

Question 24: If the mean of five consecutive integers is 30, find the largest of the numbers
A. 30 B. 28 C. 34 D. 32
Question 4. Find the value of x for which the function 3x3=9x2 is minimium

Solution
Correct option is C
3x3-9x2=0

Factorizing yield x2(3x-9)=0

x=0 or x=2.

∴ x=0 is the minimum value.

Question 24. If the mean of five consecutive integers is 30,find the largest of the numbers.
Solution
let the consecutive numbers be x, x+1, x+2,x+3, x+4.

x + x + 1 + x + 2 + x + 3 + x + 4/5 = 30

5x + 10 = 30 x 5

simplifying for x, we have
x = 140/5 = 28

x + 4 = 28 + 4 = 32 which is the largest number.

• KUFRE IKPE

C. 34+32+30+28+26 =150, 150/5 = 30 so the largest number is 34 c. pls let me know if I got it right.

0 30-01-2016 18:36:00 +0000

(x+x+1+x+2+x+3+x+4)/5=30 (5x+10)/5=30 X+2=30 X=28 The largest of the numbers x+4=28+4=32 The answer is 32-D

0 30-01-2016 18:43:00 +0000

• Joce Ekeanya

(x)+(x+1)+(x+2)+(x+3)+(x+4)/5=30 5x+10=30*5 5x=150-10 X=28 ..therefore d largest number is 32, D

0 30-01-2016 19:00:00 +0000

• Cyprian Udebuani

No 1: C

0 30-01-2016 19:17:00 +0000

• Cyprian Udebuani

No 1: 3X*3=9X*2 Collect like times 3X*3 - 9X*2=0 (3X - 9X)*3 - 2=0 (-3x)*1=0 -3X=0 -3X/3=0/3 X=0

0 30-01-2016 19:25:00 +0000

No 24 And is D

0 30-01-2016 20:09:00 +0000

• OAA Oke

Wrong working cryprain

0 31-01-2016 07:19:00 +0000

• OAA Oke

3x*3=9x*2 Collct lyk term 3x*3-9x*2=0 Dy/dx=9x*2-18x=0 Divide through by 9 X*2-2x=0 X[x-2]=0 X=0, x-2=0 X=0, x=2 For which the function is minimum therefore ur highest value is your minimum I.e x=2

0 31-01-2016 07:30:00 +0000

• OAA Oke

So the right answer is B not C

0 31-01-2016 07:31:00 +0000

• Faith Oluwabunmi Olulana

The first question is A (3)

0 31-01-2016 16:55:00 +0000