
Common Questions Ask in Post UTME Mathematics Exams. Day1
Mathematics
Chima Sunday (Tutor)
20062016 15:22:00 +0000Try your best to solve these questions. Show working on paper when necessary and include a picture of your hand written Solution in your response. Wish you the best!
1. Find the minimum point for this curve, y = 3x^{3}  9x^{2}
A. 2
B. 0
C. 1
D. 18
(uniuyo)Updated SAolution
If d^{2}y/dx^{2} < 0; its a maximum point
If d^{2}y/dx^{2} > 0; its a minimum pint
If d^{2}y/dx^{2} = 0; its a stationery point.
Thus dy/dx = 9x^{2}  18x
d^{2}y/dx^{2} = 18x  18 = 18(x  1)
at x = 0, d^{2}y/dx^{2} = 18(0  1) = 18, thus maximum point
at x = 2, d^{2}y/dx^{2} = 18(2  1) = 18, thus minimum point
So the minimum point is at x = 2
Answer is Option A2. QRS is a triangle with QS = 12m, RQS = 30^{o} and QRS = 45^{o}. Calculate the length of RS
A. 18.2m
B. 12.2m
C. 6.2m
D. 3.2m
(unilag)Updated Solution
f one should sketch the triangle, it will be seen that angle 30 is opposite to RS and 45 is opposite to 12m. By applying sine formular
sin30/RS = sin45/12
by subject formular
RS = 12sin30/sin45 = 12 × 0.5/0.707 = 8.4m
The answer is not in the Option3. Express 2cos(60 + θ) in terms of cosθ and sinθ
A. cosθ + √3sinθ
B. √3cosθ  sinθ
C. cosθ  √3sinθ
D. √3cosθ + sinθ
(uniben)Updated Solution
2cos(60 + θ) = 2[cos60cosθ  sin60sinθ] (i.e difference of double angle expansion for cosine)
cos60 = 1/2; siin60 = √/2
so 2cos(60 + θ) = 2[1/2cosθ  √3/2sinθ]
factoring 2; 2/[cosθ  √3sinθ] = cosθ  √3sinθ
Answer is Option C

Chima Sunday (Tutor)
Please, just a reminder. This post has been updated with its detailed solution. So try and check it up. Wouldn't forget to commend on the efforts of some exceptional jambites that attempted to solve the question. Your labour of work is not i vain, keep it up and keep the fire burning. I frown to some of us that demand for number when asked to post their hand written solutions to substantiate their answer. Please is not the ethics of the forum, like i said "Show working on paper when necessary and include a picture of your hand written Solution in your response" Once again thanks for attempting. Cheers!
1 22062016 11:35:00 +0000

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