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Chima Sunday (Tutor)
31052016 16:33:00 +0000Write your question here, Keep it simple and clear to get the best answer and explanation not only from the tutor, also from our over 3000 Genius in this forum.
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Jennifer Sparkle
what score those an intending medical student is expected to get in jamb?
1 31052016 16:40:00 +0000

Majiri E
pls help out... I need the workings to this question? An object weights 100N on the earth's surface .find its weight at a point P with orbital radius 2R (g=10Nkg1) A 40N B 35N C 25N D 20N
1 01062016 09:58:00 +0000

Chima Sunday (Tutor)
Simple Solution
W = mg
So our work is to use the information given to find the mass and acceleration due to gravity at that point and then multiply them.
To start with
F = W = GMm/R^{2} (Newton gravitational force)
On the earth surface with radius R, W = 100N
Then 100 = GMm/R^{2}
by subject formular m = 100R^{2}/GM ...........(1)
Equation (1) is the mass of the object
For g at that orbital radius of 2R
F = W = mg = GMm/4R^{2}
by subject formular, g = GM/4R^{2} ..........(2)
note that m cancelled each other
Now that we have our m and g, we can go ahead and multiply to obtain
W = m * g = 100R^{2}/GM * GM/4R^{2} = 100/4 = 25N
Answer is Option C1 01062016 12:36:00 +0000

Emmanuella Amarachi
A glass of initial volume 2×10^4cm^3 is heated from 20^0C to 50^0C.If the linear expansity of glass is 9×10^6k^1,the volume of the bottle at 50^0C is (a)20016.2Cm^3 (b)20005.4cm^3 (c)20008.1cm^3(d)20013.5cm^3
1 09062016 22:26:00 +0000

Emmanuella Amarachi
A glass of initial volume 2×10^4cm^3 is heated from 20^0C to 50^0C.If the linear expansity of glass is 9×10^6k^1,the volume of the bottle at 50^0C is (a)20016.2Cm^3 (b)20005.4cm^3 (c)20008.1cm^3(d)20013.5cm^3
1 09062016 22:28:00 +0000

Emmanuella Amarachi
A glass of initial volume 2×10^4cm^3 is heated from 20^0C to 50^0C.If the linear expansity of glass is 9×10^6k^1,the volume of the bottle at 50^0C is (a)20016.2Cm^3 (b)20005.4cm^3 (c)20008.1cm^3(d)20013.5cm^3
1 09062016 22:29:00 +0000

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